Archive of the former Mathematics and Computer Science Depthttps://www.univ-soukahras.dz/en/dept/mi |
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Quel est le résultat de l'équation S = A’ + B.C.A’ + A’.B’ + A+B’.C’? |
Asked on 20:19, Friday 6 May 2016 By Amara BEKHOUCH |
Answers (16)
Answer (1)
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A+A'=1 alors S=1+ B.C.A’ + A’.B’ +B'.C' S=1 |
Answered on 22:44, Wednesday 11 May 2016 by |
Answer (1)
1 votes
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S=B' ? |
Answered on 23:35, Friday 6 May 2016 by abdennour redjaibia (282 points) |
Answer (2)
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s=a'+b.c.a'+a'.b'+a+b'c'= a'(1+bc)+(a+a'b'=a+b')+b'c'=a'(1)+a+b'+b'c'=a'+a+b'(1+c')=0+b'(1)=b' |
Answered on 20:46, Saturday 7 May 2016 by abdennour redjaibia (282 points) |
Answer (3)
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S = A'(BC*B'C')+BC(A'*A)+ A'B' + B'C' = A'B' + B'C' |
Answered on 22:50, Sunday 8 May 2016 by |
Answer (4)
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S= 1 ^^ |
Answered on 03:25, Monday 9 May 2016 by abdennour redjaibia (282 points) |
Answer (6)
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araibia meriem S=1 |
Answered on 22:24, Thursday 12 May 2016 by |
Answer (8)
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kherkhache romayssa S=1 |
Answered on 11:35, Friday 13 May 2016 by |
Answer (10)
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on a S = A'+BCA'+A'B'+A+B'C' A'+BCA'=A'(1+BC)=A' A'B'+A=A+B' parce que (a+ab'=a+b) ==> S=A'+A+B'+B'C' = 1 + B'(1+C') = 1+B' ==> S= 1 |
Answered on 19:07, Saturday 14 May 2016 by |
Answer (11)
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la reponce : S=1 |
Answered on 19:14, Saturday 14 May 2016 by |
Answer (12)
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S = A'+BCA'+A'B'+A+B'C' S=A'(1+BC)+B'(A'+C')+A S=A'+A+B'=1+B' |
Answered on 20:22, Saturday 14 May 2016 by |