Archive of the former Mathematics and Computer Science Depthttps://www.univ-soukahras.dz/en/dept/mi |
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La sortie « Q » d’une bascule D prend toujours la même valeur que l’entrée D? Répondre par vrai ou faux, justifier votre réponse. |
Asked on 20:20, Friday 6 May 2016 By Amara BEKHOUCH |
Answers (14)
Answer (1)
7 votes
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NON |
Answered on 14:46, Saturday 7 May 2016 by abdennour redjaibia (282 points) |
Answer (1)
1 votes
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Non. car si H=1: Q=D sinon (H=0) Q=Q (état de mémoire). |
Answered on 21:29, Tuesday 10 May 2016 by |
Answer (2)
0 votes
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faux si H = 1 --> Q=D sinon Q = état de mémoire
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Answered on 03:30, Thursday 12 May 2016 by abdel koudous moussaoui (11 points) |
Answer (3)
1 votes
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faux si h=1 ,Q=D SINON Q=ETAT DE MEMOIRE
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Answered on 18:31, Thursday 12 May 2016 by |
Answer (4)
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Non: car si H=1: Q=D sinon (H=0) Q=Q (état de mémoire. |
Answered on 11:54, Friday 13 May 2016 by |
Answer (5)
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Non . on prend le H en considération Si H=1 ===> Q=D Sinon Q=Q (état mémoire). |
Answered on 13:55, Friday 13 May 2016 by |
Answer (6)
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Faux Si H=1 Q=D Si H=0 Qn+1=Q |
Answered on 15:04, Friday 13 May 2016 by |
Answer (7)
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bascule D_LATCH: Q=D si seulement H=1 sinon Q=Q-1 dans le cas H=0 |
Answered on 07:52, Saturday 14 May 2016 by |
Answer (8)
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faux psq si H=1: Q=D si H=0 Q=Q (état de mémoire) |
Answered on 20:09, Saturday 14 May 2016 by |
Answer (9)
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faux si H =1 ,Q=D Sinon Q= etat memoire |
Answered on 19:04, Sunday 15 May 2016 by |
Answer (10)
0 votes
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faux |
Answered on 21:20, Monday 30 Oct 2017 by khawla Necibi (52 points) |
Answer (13)
0 votes
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NON |
Answered on 17:27, Friday 8 Dec 2017 by nacer eddine ben nia (68 points) |